Cold Front Calculator#
Adapted from: “Modern Fortran: Building Efficient Parallel Applications” by Milan Curcic (Manning)
Program to Calculate the Temperature due to a Cold Front#
program cold_front
implicit none
real :: temp1 = 12 ! degrees C
real :: temp2 = 24 ! degrees C
real :: dx = 960 ! km
real :: c = 20 ! km / hr
real :: dt = 24 ! hours
real :: res ! result in degrees C
res = temp2 - c * (temp2 - temp1) / dx * dt
print *, "Temperature after ", dt, &
"hours is ", res, "degrees"
end program cold_front
The following explanation is given by “Code Copilot” within ChatGPT 4.
The Fortran program cold_front
is designed to calculate the change in temperature as a cold front moves over a given distance and time. The program uses a simple linear model to interpolate or extrapolate temperature changes based on the movement of the cold front. Here’s a detailed explanation of each component and the underlying calculations:
Variables:#
temp1
(12 degrees C): Initial temperature at the starting point.temp2
(24 degrees C): Initial temperature at a point 960 km away from the starting point.dx
(960 km): The distance between two points where the initial temperatures are measured.c
(20 km/hr): Speed of the cold front moving through the area.dt
(24 hours): Time period over which the temperature change is calculated.
Calculation:#
Temperature Difference Calculation:
temp2 - temp1
computes the temperature difference between the two points.
Temperature Change Rate:
(temp2 - temp1) / dx
calculates the rate of temperature change per kilometer.
Temperature Change Over Time:
c * (temp2 - temp1) / dx * dt
computes the total temperature change overdt
hours, considering the speed of the cold front. The termc * dt
effectively calculates the distance covered by the cold front indt
hours. Multiplying this distance by the rate of temperature change per kilometer gives the total change in temperature over that distance.
Result:#
res
: The resulting temperature after the cold front has moved fordt
hours. The calculationtemp2 - c * (temp2 - temp1) / dx * dt
adjusts the initial temperature attemp2
by the amount the temperature is expected to change due to the cold front’s movement. The subtraction here is due to the interpretation that moving through the temperature gradient causes a decrease from the starting point attemp2
.
Output:#
The program prints the resulting temperature after
dt
hours, indicating how much the temperature has changed due to the cold front’s progression.
Simplified Formula Explanation:#
The formula calculates how much the temperature decreases as the cold front moves from
temp2
towardstemp1
. This is based on the linear change in temperature over the distancedx
, scaled by how far the cold front moves indt
hours.
Usage:#
This simple program can be used in educational settings to demonstrate basic principles of linear interpolation and applying rates over time, or in a basic meteorological context to estimate temperature changes without complex modeling. It is a straightforward example of applying basic physics and arithmetic operations in a programmatic context.
Program Compilation and Execution#
The above program is compiled and run using Fortran Package Manager (fpm):
import os
root_dir = ""
root_dir = os.getcwd()
code_dir = root_dir + "/" + "Fortran_Code/Cold_Front_Calculator"
os.chdir(code_dir)
build_status = os.system("fpm build 2>/dev/null")
exec_status = os.system("fpm run 2>/dev/null")
Temperature after 24.0000000 hours is 18.0000000 degrees